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What is the simplified expression for [(p^2)(q^5)]*[(p^-4)(q^5)]^-2?

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Final answer:

The simplified expression for [(p^2)(q^5)]*[(p^-4)(q^5)]^-2 is p^10.

Step-by-step explanation:

To simplify the expression [(p^2)(q^5)]*[(p^-4)(q^5)]^-2, we can first simplify the expressions inside the parentheses.
(p^2)(q^5) = p^2 * q^5
(p^-4)(q^5) = p^-4 * q^5

Next, take the negative exponent of the second expression and reciprocate both the base and the exponent.
p^-4 = 1/(p^4).

Now substitute the simplified expressions back into the original expression:
[(p^2)(q^5)]*[(p^-4)(q^5)]^-2 = p^2 * q^5 * [1/(p^4) * q^5]^-2

Apply the rule that states that when we raise a fraction to a negative exponent, we can flip the fraction and make the exponent positive:
[1/(p^4) * q^5]^-2 = [(p^4)/q^5]^2

Now multiply the terms together:
p^2 * q^5 * [(p^4)/q^5]^2 = p^2 * (p^4)^2 = p^2 * p^8 = p^(2+8) = p^10

Therefore, the simplified expression is p^10.

User Danylo Mysak
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