Final answer:
The total number of possible outcomes for one spin of a six-sided die and one coin toss is 12. This is calculated by multiplying 6 outcomes of the die spin by 2 outcomes of the coin toss.
Step-by-step explanation:
To determine the number of possible outcomes for one spin of a six-sided die and one coin toss, we need to consider the possible outcomes for each event separately. A fair six-sided die can land on any one of six faces (1, 2, 3, 4, 5, or 6), representing six possible outcomes. A fair coin has two sides and can land on either Heads (H) or Tails (T), representing two possible outcomes.
As per the fundamental principle of counting, to find the total number of possible outcomes for two independent events, you multiply the number of outcomes for each event. So, for the die (6 possible outcomes) and the coin (2 possible outcomes), the calculation is:
6 (die outcomes) × 2 (coin outcomes) = 12
This means there are 12 possible outcomes for one spin of the die followed by one coin toss. Some of these outcomes include H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, and T6. None of the options provided in the question (5, 61, 43, or 2) are correct.