Question

If the allele for round seeds is dominant and the allele for wrinkled seeds is recessive, explain why this cross produced more offspring with round seeds than with wrinkled seeds.

Answer 1

1/2

Step-by-step explanation:

Well just study the analysis shown below,if you don't understand any point of the diagram below, let me know,but it will be better if you try to understand the way to find the nature of offsprings of your own.

this may help but im not sure if it does ur welcome

Answer 2

The cross produced more offspring with round seeds than wrinkled seeds because the allele for round seeds is dominant (RR or Rr genotypes) and the allele for wrinkled seeds is recessive (rr genotype).

If the allele for round seeds is dominant (let's represent it as "R") and the allele for wrinkled seeds is recessive (let's represent it as "r"), the cross would involve two heterozygous parents (Rr x Rr).

The genotype ratio among the F1 offspring would be 1:2:1 (RR:Rr:rr), but the phenotype ratio would be 3:1 (round:wrinkled) due to the dominance of the "R" allele.

Out of the 100 F1 offspring:25 would be RR (round)50 would be Rr (round)25 would be rr (wrinkled)So, the cross produces more offspring with round seeds (76 out of 100) than with wrinkled seeds (24 out of 100) because the presence of at least one dominant allele "R" results in a round seed phenotype.