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A biker slows to a stop at a rate of -7.5m/s/s from a velocity of 55m/s. What distance does the biker cover as they are slowing down?

A. 202 meters
B. 200 meters
C. 100 meters

1 Answer

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Final answer:

Using the kinematic equation for distance covered during deceleration, the biker covers approximately 202 meters as they slow down from an initial velocity of 55 m/s to a stop at a deceleration rate of -7.5 m/s².

Step-by-step explanation:

To determine the distance a biker covers while slowing down, we can use the kinematic equation: ∆s = v² - u² / 2a. Where ·s is the distance covered, v is the final velocity, u is the initial velocity, and a is the acceleration. In our case, the biker's initial velocity (u) is 55 m/s, the final velocity (v) is 0 m/s (since the biker comes to a stop), and the acceleration (a) is -7.5 m/s² (negative because the biker is decelerating). Plugging these values into our equation: ·s = 0² - 55² / (2 * -7.5), ·s = -3025 / -15, ·s = 201.67 meters . Therefore, the distance the biker covers as they are slowing down is approximately 202 meters (A).

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