Answer: A
Explanation:
Since multiplication is the only operation under the radical, you can apply the root to each term. Im not sure if I worded that correctly, but ill hopefully explain correctly.
First we need to take the cubed root of 648. This number doesn't have a perfect root, but it can be simplified. 648 is the same as 216*3, and 216 has a perfect cubed root of 6. So we can bring the 6 outside of the radical
![3x*6\sqrt[3]{3x^4y^8}=18x\sqrt[3]{3x^4y^8}](https://img.qammunity.org/2022/formulas/mathematics/high-school/eo2bjk3psw9w0n494kmu7wrzsvz7zzdxnz.png)
The next step is simplifying the variables, which is the easiest part. Just split them up into multiples of 3, again poor explanation but Ill show what I mean.
![18x\sqrt[3]{3x^3xy^3y^3y^2}](https://img.qammunity.org/2022/formulas/mathematics/high-school/o8aivojs3bpyuzey4bp69jnsbhi80msfa3.png)
The cubed root and the cubed power will cancel and can be brought outside the radical
![18x*xy^2\sqrt[3]{2xy^2} =18x^2y^2\sqrt[3]{3xy^2}](https://img.qammunity.org/2022/formulas/mathematics/high-school/kbiyhu1aynmgp711jbzafuiy5eyojv2h42.png)