Final answer:
The question pertains to traffic collisions, often influenced by the dynamics of a vehicle's motion such as at intersections or bus stops.
The physics problems provided are used to deduce the time it takes for a bus to travel between two stops and the average velocity, which is determined by the sum of the durations of acceleration, constant speed, and deceleration.
Step-by-step explanation:
The question seems to be referring to the physics of traffic collision scenarios and the dynamics of bus motion. In order to accurately address the student's question on the most common bus collisions, it's crucial to understand the contexts in which these collisions occur, including intersections, bus stops,
and areas with heavy traffic flow where frequent starting, stopping, and acceleration changes can lead to accidents.
Regarding the physics problem provided, we can calculate the answers as follows:
- Firstly, use the equation of motion v = u + at to find out how long the bus takes to reach the speed of 20 m/s from rest (where v is final velocity, u is initial velocity, a is acceleration, and t is time). Since the initial velocity (u) is 0 and the acceleration (a) is 2 m/s2, it takes 10 seconds to reach 20 m/s.
- Next, the bus travels at a constant speed for another 20 seconds.
- Finally, the bus decelerates uniformly to a stop in 5 seconds.
The total time taken from the first bus stop to the second is the sum of all three durations (10s + 20s + 5s = 35 seconds).
The average velocity can be calculated by dividing the total distance traveled by the total time. Here, the average velocity will be dependent on the specifics of the bus's route, including the distances covered during acceleration, constant speed, and deceleration phases.