Final answer:
The acceleration of the plane during landing is calculated using the change in velocity over the time it takes to come to rest. By dividing the change in velocity (-50 m/s) by the time (36.2 s), we get an acceleration of approximately -1.38 m/s².
Step-by-step explanation:
The student is asking about the acceleration of a plane during the landing phase. To calculate the acceleration of the airplane as it lands and comes to rest, we can use the formula a = (Δv) / t, where Δv is the change in velocity and t is the time taken for that change. In this case, the plane lands at a speed of 0.05 km/sec (or 50 m/s) and comes to rest in 36.2 seconds, so the change in velocity is -50 m/s (since it comes to rest, final velocity is 0 m/s).
To find the acceleration, we divide the change in velocity by the time: a = (-50 m/s) / 36.2 s ≈ -1.38 m/s². The acceleration is negative, indicating that it is a deceleration, as the acceleration vector is in the opposite direction of the velocity vector.