Question

Makayla was scuba diving. She started at at-80 5/9 meters below the surface. She then swam up 20 2/9 meters from her storting location for a break. Alwhat location did she stop for her break compared to sea level?

Answer 1

543/9 meters below the surface.

Step-by-step explanation:

First, we need to transform the mixed numbers into fractions, so 80 5/9 meter and 20 2/9 meters are equivalent to:

`\begin{gathered} A(b)/(c)=(A\cdot c+b)/(c) \\ 80(5)/(9)=(80\cdot9+5)/(9)=(725)/(9) \\ 20(2)/(9)=(20\cdot9+2)/(9)=(182)/(9) \end{gathered}`

Now, to calculate the location where she stops for a break, we need to take 182/9 and subtract it from 725/9. So:

`(725)/(9)-(182)/(9)=(725-182)/(9)=(543)/(9)`

Therefore, Makayla stops for a break at 543/9 meters below the surface.