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A pet store sells goldfish and hermit crabs,

The store sells 7 goldfish and 3 hermit crabs for $26.

• The store sells 4 goldfish and 5 hermit crabs for $28.

How much would the store sell 6 goldfish and 4 hermit crabs for?

1 Answer

6 votes

Answer:


Cost = \$28

Explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:


7g + 3h = 26

The second statement, we have:


4g + 5h = 28

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:


7g + 3h = 26 --- (1)


4g + 5h = 28 --- (2)

Make g the subject in (2)


4g + 5h = 28


4g = 28 - 5h

Divide both sides by 4


g = (1)/(4)(28 - 5h)

Substitute
(1)/(4)(28 - 5h) for g in (1)


7g + 3h = 26


7((1)/(4)(28 - 5h)) + 3h = 26


(7)/(4)(28 - 5h) + 3h = 26

Multiply through by 4


4 * (7)/(4)(28 - 5h) + 4*3h = 26*4


7(28 - 5h) + 4*3h = 26*4

Open bracket


196 - 35h + 12h = 104


196 -23h = 104

Collect Like Terms


-23h = 104-196


-23h = -92

Make h the subject


h = (-92)/(-23)


h = (92)/(23)


h = 4

Substitute 4 for h in
g = (1)/(4)(28 - 5h)


g = (1)/(4)(28 - 5*4)


g = (1)/(4)(28 - 20)


g = (1)/(4)(8)


g = 2

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:


Cost = 6g + 4h


Cost = 6*\$2 + 4*\$4


Cost = \$12 + \$16


Cost = \$28

User Evermean
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