Answer:
0.1M sugar < 0.1 M NaCl < 0.08M CaCl2 < 0.04 M Na2SO4
Explanations:
First we must understand that the higher thecnoncentration of a compound, the lower the melting point. This shows that 0.04 m Na2SO4 will have highest melting point followed by 0.08 M CaCl2
Since 0.1M of sBgar and 0.1M of NaCl have the same molarity, we will determine the effect of solute and ionic bonding between compound on melting point. Since common salt (NaCl) is made up of stronger ionic bonds, it will have higher melting point than sugar.
The increasing order of their melting point wile be 0.1M sugar < 0.1 M NaCl < 0.08M CaCl2 < 0.04 M Na2SO4