Question

For a fixed bias circuit, Vcc = 12 V and R_{C} = 4k*Omega The Si transistor used ischaracterized by beta = 50 ICEO = 0 and VCE sat = 0.2 V. Find the value of RB that just results in saturation.​

Answer 1

In a fixed bias circuit with given values for Vcc, RC, β, ICEO, and VCE sat, the value of RB that results in saturation is 192.37 kΩ.

Step-by-step explanation:

In a fixed bias circuit, the value of RB that results in saturation can be determined by analyzing the transistor characteristics.

Given Vcc = 12 V, RC = 4kΩ, β = 50, ICEO = 0, and VCE sat = 0.2 V, we can use the equation for the transistor current:

ICE = β * IB

Since the transistor is in saturation, the collector-emitter voltage (VCE) is less than the saturation voltage (VCE sat). We can calculate the current through RC:

IC = (Vcc - VCE sat) / RC

With the given values, we have:

IC = (12 V - 0.2 V) / 4kΩ = 2.95 mA

Since IC = β * IB, we can solve for IB:

IB = IC / β = 2.95 mA / 50 = 0.059 mA

Finally, we can calculate the value of RB:

RB = (Vcc - VBE) / IB = (12 V - 0.7 V) / 0.059 mA = 192.37 kΩ