Question

Bromine and chlorine gas react to give bromine monochloride (BrCl) according to Br2(g) Cl2(g)⇌2BrCl(g) Given initial concentrations [Br2]=1.20 mol L-1, [Cl2]=0.70 mol L-1 and [BrCl]=0 and K=7 determine (to two decimal places) the equilibrium concentration of BrCl in mol L-1

Answer 1

The equilibrium concentration of BrCl is approximately 1.27 mol/L.

To determine the equilibrium concentration of BrCl, we can use the given initial concentrations and the equilibrium constant (K). The equilibrium constant expression for the reaction is K = [BrCl]2/([Br2][Cl2]). Substitute the given values into the expression and solve for [BrCl].

K = [BrCl]2/([Br2][Cl2]) = 7

[BrCl] = √(K*[Br2][Cl2]) = √(7*1.20*0.70) ≈ 1.27 mol/L