The percent absolute humidity when compressing the air to 110 °F and 2 psig is 59.11%.
Step-by-step explanation:
Absolute Humidity (%) = (Pw / Pdry) * 100; Pw = Partial pressure of water vapor at the new temperature and pressure and Pdry = Partial pressure of dry air at the new temperature and pressure
Pdry = (Ptotal - Pw) = (2 psig - 0.7429 psig) = 1.2571 psig
Given that Pw = P*H2O at 110 °F = 0.7429 psi, we will plug these values into the formula for absolute humidity.
Absolute Humidity (%) = (0.7429 psi / 1.2571 psi) * 100
= 0.590963328
= 59.10%.