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Activity 2: Time is Gold! Directions: Analyze the following situations and answer the questions that follow. 1. Raizza is on board a plane that was scheduled to arrive at 10:30 AM. When it landed at the airport, it was delayed by 1 hour and 15 minutes. What time did the plane arrive? 2. Mr. de Guzman's travel time from home to workplace or vice versa is 30 minutes. He works for 7 hours and 30 minutes and eats lunch for 45 minutes. How much time does he spend away from home? Explain your answer. 3. Abet slept for 8 hours and 18 minutes. If he went to bed at 10:41 PM, what time did he wake up in the morning? How many minutes did he sleep? ​

2 Answers

4 votes

Final answer:

Raizza's delayed flight arrives at 11:45 AM, Mr. de Guzman spends 8 hours and 15 minutes away from home daily considering his work and travel time, and Abet wakes up at 6:59 AM after sleeping for 498 minutes.

Step-by-step explanation:

These questions involve calculating elapsed time, adding and subtracting time intervals, and applying these concepts to real-life situations.

  1. Raizza's Flight Arrival Time: The plane was scheduled to arrive at 10:30 AM. With a delay of 1 hour and 15 minutes, the new arrival time is calculated by adding the delay to the scheduled arrival time. Thus, 10:30 AM + 1 hour = 11:30 AM, and then adding 15 minutes results in an arrival time of 11:45 AM.
  2. Mr. de Guzman's Time Away From Home: He travels for 30 minutes to work and 30 minutes back home, works for 7 hours and 30 minutes, and has a lunch break of 45 minutes. The total time away from home is the sum of all these durations: 30 min (to work) + 30 min (back home) + 7 hr 30 min (work) + 45 min (lunch) = 8 hours and 15 minutes away from home.
  3. Abet's Wake Up Time: Abet slept for 8 hours and 18 minutes. To find the wake-up time, we add the sleep duration to the bedtime. Starting from 10:41 PM, adding 8 hours brings us to 6:41 AM. Then, adding 18 minutes results in a wake-up time of 6:59 AM. He slept for a total of 498 minutes (8 hours is 480 minutes plus 18 minutes).
User Shubniggurath
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4 votes

Final answer:

To find the arrival time of the delayed plane, add the delay time to the scheduled arrival time. Calculate the time spent away from home by subtracting working hours and lunch break. Calculate the wake-up time by subtracting sleep duration from the bedtime.

Step-by-step explanation:

To find the arrival time of the plane, we need to add the delay time to the scheduled arrival time. The plane was delayed by 1 hour and 15 minutes, which is equivalent to 75 minutes. So, we add 75 minutes to 10:30 AM, which gives us 11:45 AM as the arrival time.

To calculate the amount of time Mr. de Guzman spends away from home, we need to subtract his working hours and lunch break from the total time. He works for 7 hours and 30 minutes and has a lunch break of 45 minutes. So, the total time he spends away from home is 7 hours and 30 minutes + 45 minutes = 8 hours and 15 minutes.

To find out what time Abet woke up in the morning, we need to subtract the sleep duration from the time he went to bed. Abet slept for 8 hours and 18 minutes, which is equivalent to 498 minutes. Subtracting 498 minutes from 10:41 PM, we get 2:23 AM as the wake-up time. He slept for 498 minutes.

Learn more about Time here:

User Jeff Vdovjak
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