Answer:
The diagonal is irrational because it is a product of a rational and an irrational number
Explanation:
The options are not given. However, the question is still answerable.
Given
Shape: Square
Length: Rational
Since the side length is said to be rational, I'll answer the question based on whether the diagonal is rational or not.
Having said that:
The diagonal (d) of a square with side length (l) is calculated using Pythagoras theorem.
![d^2 = l^2 + l^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/4wwhgqi3r9vuqado1my40h20nhypromdye.png)
![d^2 = 2l^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/yq9x7et4bqxg8pxvyfcqwpjpxt21558ziw.png)
Take positive square root of both sides
![d = √(2l^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/5k079mbytfwx2syhhkcn7duenxu8eni75p.png)
Split:
![d = √(2) * √(l^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/on72wb9d8njrihl0ba7r5z8lalvlmbo9yb.png)
![d = √(2) *l](https://img.qammunity.org/2022/formulas/mathematics/high-school/58fkyvuvg0x49v91hve60hyvt38jvyw2zo.png)
Recall that the side length (l) is rational.
However,
is irrational.
So, the product of l and
will be irrational
Hence:
The diagonal is irrational