Question

you're carrying a 4 m long, 19 kg pole to a construction site when you decide to stop for a rest. you place one end of the pole on a fence post and hold the other end of the pole 30 cm from its tip. how much upward force must you exert to keep the pole motionless in a horizontal position?

Answer 1

To keep the pole motionless in a horizontal position, you need to exert an upward force equal to its weight, which is 186.2 N.

Step-by-step explanation:

To keep the pole motionless in a horizontal position and prevent it from tipping over, you need to exert an upward force equal to the weight of the pole. The weight of an object can be calculated by multiplying its mass by the acceleration due to gravity. In this case, the mass of the pole is given as 19 kg. The acceleration due to gravity is approximately 9.8 m/s².

The weight of the pole can be calculated as follows:

Weight = mass x acceleration due to gravity

Weight = 19 kg x 9.8 m/s²

= 186.2 N

Therefore, you need to exert an upward force of 186.2 N to keep the pole motionless in a horizontal position.