Question

For Event D, compute the absolute relative difference ∣f 5000−P(D)∣ P(D), where f5000 is the relative frequency of Event D on the 5,000th trial and P(D) is the classical probability of Event D. Round your answer to three decimal places.

Answer 1

The absolute relative difference ∣f5000−P(D)∣ / P(D) for Event D is computed as per the given information.

Step-by-step explanation:

The explanation involves calculating the absolute relative difference between the relative frequency of Event D on the 5,000th trial (f5000) and the classical probability of Event D (P(D)). The formula for absolute relative difference is given as ∣f5000−P(D)∣ / P(D). Once the values of f5000 and P(D) are determined, plug them into the formula and calculate the result. Ensure the subtraction is performed before taking the absolute value, and then divide by P(D). Round the final answer to three decimal places as per the question's instructions.

To elaborate, if the relative frequency of Event D on the 5,000th trial (f5000) is, for example, 0.3, and the classical probability of Event D (P(D)) is 0.25, the absolute relative difference would be ∣0.3−0.25∣ / 0.25 = 0.05 / 0.25 = 0.2, which can be expressed as 20% when converted to a percentage. This signifies a 20% difference between the observed relative frequency and the expected classical probability of Event D.

In summary, the absolute relative difference is calculated by subtracting the classical probability of Event D from the relative frequency of Event D on the 5,000th trial, taking the absolute value of the result, and then dividing this by the classical probability. The obtained value represents the extent of the discrepancy between the observed relative frequency and the expected classical probability, quantified as a percentage difference.