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An experiment measures the temperature of a 800 g g substance while steadily supplying heat to it. The figure shows the results of the experiment. What is the heat of fusion?

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To melt 800 g of ice at 0°C, you would need to supply 267,200 joules of heat energy of 267,200 J

The heat of fusion is the amount of heat energy required to change 1 gram of a solid substance into a liquid at its melting point under constant pressure.

The heat of fusion of water is 334 J/g or 80 cal/g. This means that it takes 334 joules of heat energy to change 1 gram of ice at 0°C into 1 gram of water at 0°C.

The heat of fusion of a substance can be calculated using the following equation:

Q = m * L_f

where:

Q is the amount of heat energy required to melt the substance (J or cal)

m is the mass of the substance (g)

L_f is the latent heat of fusion of the substance (J/g or cal/g)

Q = 800 g * 334 J/g

Q= 267,200 J

An experiment measures the temperature of a 800 g g substance while steadily supplying-example-1
User Connie King
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