59.8k views
4 votes
Please help. It’s algebra 2

Please help. It’s algebra 2-example-1
User Tulani
by
7.8k points

1 Answer

2 votes

The polynomial function of least degree with rational coefficients, a leading coefficient of 1, and the given value of 4.6 - √7 is:


f(x) = x^2 - 7 (in standard form)

How to create a polynomial function

To create a polynomial function of least degree with rational coefficients, a leading coefficient of 1, and the given value of 4.6 - √7, use the concept of conjugate pairs.

The conjugate of √7 is -√7.

The conjugate pairs allow us to eliminate the irrational part (√7) by utilizing the difference of squares. The product of a conjugate pair results in a rational expression.

Let's denote x as the irrational part (√7) and create the polynomial function:


f(x) = (x - (\sqrt7))(x - (-\sqrt7))

Expanding the expression:


f(x) = (x - \sqrt7)(x + \sqrt7)\\f(x) = x^2 - \sqrt7x + \sqrt7x - (\sqrt7)(-\sqrt7)\\f(x) = x^2 - (\sqrt7)(-\sqrt7)\\f(x) = x^2 - 7

Therefore, the polynomial function of least degree with rational coefficients, a leading coefficient of 1, and the given value of 4.6 - √7 is:


f(x) = x^2 - 7 (in standard form)

User Cvogt
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories