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Can someone help me evaluate the sum?

Can someone help me evaluate the sum?-example-1
User PLPeeters
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1 Answer

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The calculated value of the sigma notation
\sum\limits^(120)_(n=0) 0.5(1.2)^n is 15875211.8647

How to evaluate the sigma notation

From the question, we have the following parameters that can be used in our computation:


\sum\limits^(120)_(n=0) 0.5(1.2)^n

From the above, we have

First term, a = 0.5

Common ratio, r = 1.2

Number of terms, n = 121

The sum of the sigma notation is represented as


\sum\limits^(120)_(n=0) 0.5(1.2)^n = (a(r^n - 1))/(n - 1)

Substitute the known values into the equation


\sum\limits^(120)_(n=0) 0.5(1.2)^n = (0.5 * (1.2^(121) - 1))/(121 - 1)

Evaluate


\sum\limits^(120)_(n=0) 0.5(1.2)^n = 15875211.8647

Hence, the value of the sigma notation
\sum\limits^(120)_(n=0) 0.5(1.2)^n is 15875211.8647

User Gulsen
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