Question

Can someone help me evaluate the sum?

Answer 1

The calculated value of the sigma notation
`\sum\limits^(120)_(n=0) 0.5(1.2)^n` is 15875211.8647

How to evaluate the sigma notation

From the question, we have the following parameters that can be used in our computation:

`\sum\limits^(120)_(n=0) 0.5(1.2)^n`

From the above, we have

First term, a = 0.5

Common ratio, r = 1.2

Number of terms, n = 121

The sum of the sigma notation is represented as

`\sum\limits^(120)_(n=0) 0.5(1.2)^n = (a(r^n - 1))/(n - 1)`

Substitute the known values into the equation

`\sum\limits^(120)_(n=0) 0.5(1.2)^n = (0.5 * (1.2^(121) - 1))/(121 - 1)`

Evaluate

`\sum\limits^(120)_(n=0) 0.5(1.2)^n = 15875211.8647`

Hence, the value of the sigma notation
`\sum\limits^(120)_(n=0) 0.5(1.2)^n` is 15875211.8647