Answer:
y = -
x + 20
Explanation:
The first step is to find the point of intersection of the 2 given lines.
x + y = 10 → (1)
3x - 4y + 12 = 0 ( subtract 12 from both sides )
3x + 4y = - 12 → (2)
multiplying (1) by 4 and adding the result to (2) will eliminate y
4x + 4y = 40 → (3)
add (2) and (3) term by term to eliminate y
(3x + 4x) + (- 4y + 4y) = - 12 + 40
7x + 0 = 28
7x = 28 ( divide both sides by 7 )
x = 4
substitute x = 4 into either of the 2 original equations and solve for x
substituting into (1)
4 + y = 10 ( subtract 4 from both sides )
y = 6
point of intersection is (4, 6 )
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = -
x +9 ← is in slope- intercept form
with slope m = -
• Parallel lines have equal slopes , then
y = -
x + c ← is the partial equation
to find c, substitute (4, 6 ) for x and y into the partial equation
6 = -
(4) + c = - 14 + c ( add 14 to both sides )
20 = c
y = -
x + 20 ← equation of parallel line