Question

Help please I don't understand where to get the degrees from. And what degrees are each

Answer 1

(i)

`\begin{gathered} \sin \text{ }\theta\text{ = }\cos \text{ }\theta \\ \end{gathered}`

Sine of an angle is complementary to the Cosine of an angle so for both to be the same the angle 90 degrees must be divided into.

`\theta=45^0`

(ii)

`\begin{gathered} \tan \text{ }\theta\text{ = 0} \\ \theta\text{ = }\tan ^(-1)(0) \\ \theta\text{ = 0} \end{gathered}`

(iii)

`\csc \text{ }\theta\text{ > sec }\theta`

As said earlier sine and cosine of angles are complementary so cosecant and secant of angles are also complementary.

`\begin{gathered} \text{When }\theta\text{ = 30} \\ \csc \text{ }\theta\text{ > sec }\theta \\ (1)/(\sin30)\text{ > }(1)/(\cos30) \\ \\ 2\text{ > 1.15} \\ \\ \csc \text{ }\theta\text{ > sec }\theta\text{ when }\theta=30^0 \end{gathered}`