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Solve for xx. Round to the nearest tenth of a degree, if necessary

Solve for xx. Round to the nearest tenth of a degree, if necessary-example-1

1 Answer

5 votes

Answer:

x = 55°

Explanation:

Given:

  • Adjacent = OP = 5.1
  • Hypotenuse = OQ = 8.9

To find:

x° = ?

Solution:

The cosine of an angle is defined as the ratio of the adjacent side to the hypotenuse of a right triangle.


\sf cos (x) = (adjacent )/( hypotenuse)

In this case, the adjacent side is 5.1 and the hypotenuse is 8.9.

Therefore, the cosine of angle x is:


\sf cos(x) =(OP)/(OQ)\\\\ =( 5.1)/(8.9)\\\\ = 0.5730337078651

To find the angle x in degrees, we can use the following formula:


\sf angle( x )= cos^(-1)(cos x)


\sf angle( x )= cos^(-1)( 0.5730337078651 )


\sf angle( x ) = 55.037952471005

In nearest tenth


\sf angle( x ) \approx 55.0

Therefore, the angle x is 55°

User SteveP
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