Find the zeros of g(x) = 2x² + 32. The zeros of g are x = and x =

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asked Dec 20, 2024 42.2k views

1 Answer

Ben Boyle · Answer 1 · 2024-12-25T14:38:14+0000

The zeros of the function g(x) = 2x² + 32 are x = 4i and x = -4i.

To find the zeros of the function g(x) = 2x² + 32, we need to solve the equation for x when g(x) = 0.

Setting g(x) = 0, we get:

2x² + 32 = 0

Subtracting 32 from both sides, we have:

2x² = -32

Dividing both sides by 2, we get:

x² = -16

Taking the square root of both sides, we get:

x = ±4i

Therefore, the zeros of g(x) are x = 4i and x = -4i.