Question

Find the zeros of g(x) = 2x² + 32.
The zeros of g are x =
and x =

Answer 1

The zeros of the function g(x) = 2x² + 32 are x = 4i and x = -4i.

Step-by-step explanation:

To find the zeros of the function g(x) = 2x² + 32, we need to solve the equation for x when g(x) = 0.

Setting g(x) = 0, we get:

2x² + 32 = 0

Subtracting 32 from both sides, we have:

2x² = -32

Dividing both sides by 2, we get:

x² = -16

Taking the square root of both sides, we get:

x = ±4i

Therefore, the zeros of g(x) are x = 4i and x = -4i.

Learn more about Finding the zeros of a quadratic function