122k views
0 votes
Decipher the code: o zpbr rbrtunpfu, strm’y o lomf!

1 Answer

3 votes

The given code "o zpbr rbrtunpfu, strm’y o lomf!" seems to be written in a substitution cipher. In a substitution cipher, each letter in the original message is replaced with a different letter or symbol.

To decipher the code, we need to determine the substitution key, which maps each coded letter to its original letter. Without additional information or context, it is challenging to determine the exact substitution key. However, we can use some general strategies to attempt to decipher the message.

One common approach is frequency analysis. In English, certain letters occur more frequently than others. For example, the most common letter is "E," followed by "T," "A," and "O." By analyzing the frequency of letters in the coded message, we can make educated guesses about the substitution key.

Let's examine the frequency of letters in the given code:

o zpbr rbrtunpfu, strm’y o lomf!

Based on the frequency of letters, we can make some initial assumptions. The letter "O" appears twice, suggesting it might correspond to a common letter like "E" or "T." Similarly, the letter "R" appears three times, indicating it might correspond to a frequently used letter like "A" or "O."

Now, we can use these assumptions to form a preliminary substitution key and decipher the message accordingly:

o -> E

z -> T

p -> H

b -> I

r -> S

u -> N

f -> G

s -> L

t -> M

m -> Y

y -> F

l -> O

Using this preliminary substitution key, we can decipher the code as follows:

o zpbr rbrtunpfu, strm’y o lomf!

E THIS IS SECRET, FIND’E A LONG!

(tell me if this is wrong or not)

I hoped this helped :D

User Markus Hofmann
by
7.3k points