Question

The angle of elevation to the top of a 10-story skyscraper ismeasured to be 3° from a point on the ground 2000 feet fromthe building. What is the height of the skyscraper to thenearest hundredth of a foot?

Answer 1

The height is 104.82 feet

EXPLANATION :

The angle of elevation to the top of the building is 3 degrees from a point that is 2000 feet away from the building.

Using tangent function :

`\tan\theta=\frac{\text{ opposite}}{\text{ adjacent}}`

The opposide side to the angle is H and the adjacent side is 2000 feet.

Then :

`\begin{gathered} \tan3=(H)/(2000) \\ \\ H=2000\tan3 \\ H=104.816\sim104.82\text{ }ft \end{gathered}`