Answer:
Let's substitute the given values of \(x\) and \(y\) into the expression \(x^2 + 3 - y^2\):
\[
(-3)^2 + 3 - 2^2
\]
Now, calculate the values within parentheses first:
\[
= 9 + 3 - 4
\]
Next, perform the addition and subtraction:
\[
= 12 - 4
\]
\[
= 8
\]
Therefore, when \(x = -3\) and \(y = 2\), the value of \(x^2 + 3 - y^2\) is \(8\).