Question

A basket contains 5 pieces of paper numbered from 1 to 5. A hat contains the letters A, B, C and D. If a blindfolded person picks a number and then a letter, what is the probability that the number is greater than 3 AND the letter is C?

Answer 1

We have a basket and a hat.

The basket has the numbers 1, 2, 3, 4 and 5.

The hat contains the letters A, B, C and D.

We have to calculate the probabiltiy of drawing a number that is greater than 3 from the basket and drawing the letter C from the hat.

We have two events:

- Drawing a number greater than 3 from the basket

- Drawing a C from the hat

They are independent as the probability of each on does not depend on the outcome of the other event.

Then, we can calculate the probability of the two events happening together as the product of its probabilities:

`P(n>3&l=C)=P(n>3)\cdot P(l=C)`

The probability of drawing a number greater than 3 can be described as 2/5, as we have 2 numbers greater than 3 (4 and 5) out of 5 numbers in the basket.

The probability of drawing a letter C can be described as 1/4, as we have one letter C out of 4 letters available.

Then, we can calculate the probability as:

`\begin{gathered} P(n>3&l=C)=P(n>3)\cdot P(l=C) \\ P(n>3&l=C)=(2)/(5)\cdot(1)/(4)=(2)/(20)=(1)/(10) \end{gathered}`

Answer: the probability is 1/10 or 0.1.