Final answer:
To find the constant 'd' that makes 'x=-3' an extraneous solution in the equation '√25+3x=d+2x', we substitute 'x=-3' into this equation and solve for 'd'. We find that when 'd' equals 10, 'x=-3' becomes an extraneous solution.
Step-by-step explanation:
To identify which value of the constant d renders x=-3 as an extraneous solution in the equation √25+3x=d+2x, we first substitute x=-3 into the equation to observe if the resulting value for d is pragmatic.
After substituting, the equation now forms: √25+3(-3)=d+2(-3).
This simplifies down to √25-9=d-6, which further simplifies to d=√16+6, hence d=10.
This means that when d=10, x=-3 will be an extraneous solution. An extraneous solution is a solution that doesn't actually satisfy the original equation, supposedly generated from the process of solving the equation.
Learn more about Extraneous Solutions