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2

Oy=x+2
Oy=2x-4
O y = x + ²/
© y = x -
The point-slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y-3=(x-1). What is
he slope-intercept form of the equation for this line?
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Answer 1

The slope-intercept form of the equation for the line passing through (-9, -2) and (1, 3) is y = (1/2)x + 5/2.

Step-by-step explanation:

The slope-intercept form of an equation is given by y = mx + b, where m is the slope and b is the y-intercept.

To find the slope, we can use the formula (y2 - y1)/(x2 - x1). From the given points, (-9, -2) and (1, 3), we have a change in y of 3 - (-2) = 5, and a change in x of 1 - (-9) = 10. Therefore, the slope is 5/10 = 1/2.

Now, we substitute one of the given points, say (1, 3), into the equation y = mx + b to find the y-intercept. We have 3 = (1/2)(1) + b, which simplifies to b = 3 - 1/2 = 5/2.

Therefore, the slope-intercept form of the equation for this line is y = (1/2)x + 5/2.

Learn more about slope-intercept form of an equation