Answer:
y = -(2/5)x - (16/5)
assuming the goal is to find the equation of a line.
Explanation:
Does the question ask for a line equation that includes these two points?
If so:
Lets look for an equation of the form y = mx + b, where m is the slope and b is the y-intercept (the value of y when x is zero).
Slope, m, is the Rise/Run between two points.
(-3,-2) to (2,-4)
Rise = (-4 - (-2)) = -2
Run = (2 - (-3)) = 5
Slope = -(2/5)
The equation becomes y = -(2/5)x + b
To find b, use one of the two given points and solve for b:
y = -(2/5)x + b
-4 = -(2/5)*2 + b for (2,-4)
-4 = -(4/5) + b
b = -3 (1/5) or -(16/5)
See the attached graph.
The equation is y = -(2/5)x - (16/5)