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Lim x tends to 2. Evaluate x^2 -4 /x-2

User Ansev
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1 Answer

3 votes

Answer:

4

Explanation:


\lim_(x \to \22) ((x^2-4)/(x-2) )
If you solve by substituting 2 into the function, you get indeterminate form where the limit of the numerator and denominator are both 0. Instead, you can factor the numerator


\lim_(x \to \22)(x^2-4)/(x-2) = \lim_(x \to \22)((x+2)(x-2))/(x-2)
From here, you can "cancel out" the (x-2) term and you are left with


\lim_(x \to \22) (x+2)
Substitute 2 for x, and you get 2 + 2 = 4.

User Vikramsjn
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