149k views
5 votes
What is the equation of a line, in point-slope form, that passes through (−2, −6)and has a slope of 13?

Responses

y+6=13(x+2)
y plus 6 equals fraction 1 over 3 end fraction open parenthesis x plus 2 close parenthesis

y+2=13(x+6)
y plus 2 equals fraction 1 over 3 end fraction open parenthesis x plus 6 close parenthesis

y−2=13(x−6)
y minus 2 equals fraction 1 over 3 end fraction open parenthesis x minus 6 close parenthesis

y−6=13(x−2)

User JustDan
by
7.6k points

1 Answer

5 votes


(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-6})\hspace{10em} \stackrel{slope}{m} ~=~ 13 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{13}(x-\stackrel{x_1}{(-2)}) \implies \boxed{y +6 = 13 ( x +2)}

User Lawrence Kok
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories