Question

What is the equation of a line, in point-slope form, that passes through (−2, −6)and has a slope of 13?

Responses

y+6=13(x+2)
y plus 6 equals fraction 1 over 3 end fraction open parenthesis x plus 2 close parenthesis

y+2=13(x+6)
y plus 2 equals fraction 1 over 3 end fraction open parenthesis x plus 6 close parenthesis

y−2=13(x−6)
y minus 2 equals fraction 1 over 3 end fraction open parenthesis x minus 6 close parenthesis

y−6=13(x−2)

Answer 1

`(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-6})\hspace{10em} \stackrel{slope}{m} ~=~ 13 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{13}(x-\stackrel{x_1}{(-2)}) \implies \boxed{y +6 = 13 ( x +2)}`