Question

Given: <B and <D are right angles;C is the midpoint of BD.

Prove:ΔABC =ΔEDC​

Answer 1

Explanation:

Statements Reasons

In
`\triangle ^(s)` ABC and EDC

1.
`\angle \: ABC = \angle \: CDF [ A ]` Both are 90° [ Given }

2. BC = CD [ S ] C is the midpoint of BD [ Given ]

3.
`\angle \: BAC = \angle \: CED [ A ]` Alternate angles

4.
`\triangle ABC \cong \triangle \: EDC \:` By AAS axiom

Hence Proved !

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