Question

Four neighbors have house numbers that are

consecutive odd integers. The sum of their house
numbers is 5720. What are the house numbers?
First house number =
Second house number =
Third house number =
Fourth house number =

Answer 1

Let's call the house numbers of the four neighbors x, x+2, x+4, and x+6, where x is the smallest odd integer. The sum of their house numbers is 5720, so we can write the equation:

x + (x+2) + (x+4) + (x+6) = 5720

Now, combine like terms:

4x + 12 = 5720

Subtract 12 from both sides:

4x = 5708

Now, divide by 4 to solve for x:

x = 5708 / 4

x = 1427

So, the house numbers are:

First house number = x = 1427

Second house number = x + 2 = 1427 + 2 = 1429

Third house number = x + 4 = 1427 + 4 = 1431

Fourth house number = x + 6 = 1427 + 6 = 1433

The house numbers are 1427, 1429, 1431, and 1433.