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1 vote
Solve kx + 12 = 3kx for x..

OA. x=-
X
1
OB. x=!
X=
O
669
314
O C. x=-6
D. x=3/
X
64

Solve kx + 12 = 3kx for x.. OA. x=- X 1 OB. x=! X= O 669 314 O C. x=-6 D. x=3/ X 64-example-1

1 Answer

2 votes

Answer:

Hi,

Answer B

Explanation:

To solve the equation kx+12=3kx for x, you'll need to isolate x on one side of the equation. Here's how you can do that:

First, move all terms involving x to one side of the equation. To do this, subtract kx from both sides:

kx−kx+12=3kx−kx

This simplifies to:

12=2kx

Now, you have 12 on one side and 2kx on the other side. To solve for x, divide both sides by 2k:


(12)/(2k) =(2kx)/(2k) \\

This simplifies to:


(12)/(2k) =x

Finally, simplify further by dividing both the numerator and denominator by 2:


(6)/(k) =x

So, the solution for x is


x=(6)/(k)

In summary:


kx+12=3kx\\\\12=3kx-kx\\\\12=2kx\\\\6=kx\\\\x=(6)/(k)\ (if\ k \\eq 0)

User Hikarikuen
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