Answer:
the energy released by an electron in a chromium atom to produce a photon of light with a wavelength of 471.8 nm is approximately 4.21 x 10^-16 joules.
Step-by-step explanation:
To calculate the energy released by an electron in a chromium atom to produce a photon of light with a wavelength of 471.8 nm, you can use the equation:
E = hc / λ
Where:
E is the energy of the photon in joules.
h is Planck's constant, which is approximately 6.626 x 10^-34 J·s.
c is the speed of light, which is approximately 3.00 x 10^8 m/s.
λ is the wavelength of the light in meters.
First, you need to convert the wavelength from nanometers (nm) to meters (m):
λ = 471.8 nm = 471.8 x 10^-9 m
Now, you can calculate the energy:
E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (471.8 x 10^-9 m)
E ≈ (1.9878 x 10^-25 J·m) / (471.8 x 10^-9 m)
E ≈ 4.21 x 10^-16 J
So, the energy released by an electron in a chromium atom to produce a photon of light with a wavelength of 471.8 nm is approximately 4.21 x 10^-16 joules.
Hope this helps you out.