Question

A blue line occurs at 471.8 nm in the emission spectrum of chromium. What amount of energy, in joules, must be released by an electron in a chromium atom to produce a photon of this light?

Answer 1

the energy released by an electron in a chromium atom to produce a photon of light with a wavelength of 471.8 nm is approximately 4.21 x 10^-16 joules.

Step-by-step explanation:

To calculate the energy released by an electron in a chromium atom to produce a photon of light with a wavelength of 471.8 nm, you can use the equation:

E = hc / λ

Where:

E is the energy of the photon in joules.

h is Planck's constant, which is approximately 6.626 x 10^-34 J·s.

c is the speed of light, which is approximately 3.00 x 10^8 m/s.

λ is the wavelength of the light in meters.

First, you need to convert the wavelength from nanometers (nm) to meters (m):

λ = 471.8 nm = 471.8 x 10^-9 m

Now, you can calculate the energy:

E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (471.8 x 10^-9 m)

E ≈ (1.9878 x 10^-25 J·m) / (471.8 x 10^-9 m)

E ≈ 4.21 x 10^-16 J

So, the energy released by an electron in a chromium atom to produce a photon of light with a wavelength of 471.8 nm is approximately 4.21 x 10^-16 joules.

Hope this helps you out.