Question

Consider a 0.9 kg object traveling in a circle of radius 6 meters. The object completes 1 circles in 2 seconds traveling at constant speed. What net force is required to sustain this motion? [Hint: 2 is almost equal to 10.]

Answer 1

Mass of the object, m= 0.9 kg and radius of the circular path, r = 6 m and time, T = 2 seconds.

Here, the velocity will be

`\begin{gathered} v=(dis\tan ce)/(time) \\ =(2\pi r)/(T) \end{gathered}`

The force required to sustain this motion is

`F=(mv^2)/(r)`

Substituting the value of velocity, we get

`\begin{gathered} F=(m(2\pi r)^2)/(rT^2) \\ =(4m\pi^2r)/(T^2) \\ =(4*0.9*10*6)/(2^2) \\ =54\text{ N} \end{gathered}`