Question

How many liters of solution would it take to make a 0.250 M solution when you have 3.52 moles of solute?

Answer 1

To make a 0.250 M solution using 3.52 moles of solute, you would need 14.08 liters of solution. This is calculated by dividing the number of moles of solute by the desired molarity.

Step-by-step explanation:

To calculate the volume of a 0.250 M solution required to dissolve 3.52 moles of solute, we use the formula Molarity (M) = moles of solute / Liters of solution. Thus, we rearrange the formula to solve for the Liters of solution: Liters of solution = moles of solute / Molarity (M).

Substituting the given values into the equation, we get:

Liters of solution = 3.52 moles / 0.250 M

Doing the math: Liters of solution = 14.08 liters. So, it would take 14.08 liters of solution to make a 0.250 M solution with 3.52 moles of solute.

Answer 2

The volume of solution in liters required to make a 0.250 M solution from 3.52 moles of solute is 14.08 liters of solution

Step-by-step explanation:

The question relates to the definition of the concentration of a solution which is the number of moles per liter (1 liter = 1 dm³) of solution

Therefore we have;

The concentration of the intended solution = 0.250 M

Therefore, the number of moles per liter of the required resolution = 0.250 moles

Therefore, the concentration of the required solution = 0.250 moles/liter

The volume in liters of the required solution that will have 3.52 moles of the solute is given as follows;

The required volume of solution = The number of moles of the solute/(The concentration of the solution)

∴ The required volume of solution = 3.52 moles/(0.250 moles/liter) = 14.08 liters

The required volume of solution to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

Therefore the number of liters required to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.