Question

Tommy throws a ball from the balcony of his apartment down to the street. The height of the ball, in meters, is modeled by the function shown in the graph. What's the average rate of change of the height of the ball, in meters per second, while it's in the air?Question options:A) 2∕3B) –2∕3C) –3∕2D) 3∕2

Answer 1

The average rate of change of the height of the ball is given by

`(f(b)-f(a))/(b-a)`

Here,

`\begin{gathered} a=0 \\ b=10 \\ f(a)=f(0)=15 \\ f(b)=f(10)=0 \end{gathered}`
`\begin{gathered} AverageRate=(f(b)-f(a))/(b-a) \\ AverageRate=(0-15)/(10-0) \\ AverageRate=(-15)/(10) \\ AverageRate=-(3)/(2) \end{gathered}`

The average rate is -3/2

Option C