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In the figure, JT = 3x + 5, CT = 76 and CJ = 6x + 8.

In the figure, JT = 3x + 5, CT = 76 and CJ = 6x + 8.-example-1

1 Answer

4 votes

Answer:

JT = 26

Explanation:

We are given the following information:

JT = 3x + 5

CT = 76

CJ = 6x + 8

We want to find JT so that CT = CJ + JT.

Since CT is a line where J lies in it. So,

CT = CJ + JT

Substitute the values:

76 = (6x + 8) + (3x + 5)

Now, combine like terms:

76 = 6x + 8 + 3x + 5

Combine the constants:

76 = (6x + 3x) + (8 + 5)

Combine like terms on both sides of the equation:

76 = 9x + 13

Now, isolate 9x by subtracting 13 from both sides of the equation:

76 - 13 = 9x

63 = 9x

Now, divide both sides by 9 to solve for x:


\sf x =( 63 )/(9)

x = 7

Now that we've found the value of x, we can find JT:

JT = 3x + 5

JT = 3(7) + 5

JT = 21 + 5

JT = 26

So, JT = 26.

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