Question

A line has a slope of -3 and passes through the point (7, -17)

right its equation to slope intercept form

Answer 1

Answer: y = -3x + 4.

Step-by-step explanation:The equation of a line can be written in slope-intercept form as y = mx + b, where m represents the slope and b represents the y-intercept.

Given that the line has a slope of -3 and passes through the point (7, -17), we can substitute the values into the slope-intercept form to find the equation of the line.

Using the point-slope form of a line, we have:

y - y₁ = m(x - x₁)

Substituting the values, we have:

y - (-17) = -3(x - 7)

Simplifying, we get:

y + 17 = -3x + 21

Next, we can rearrange the equation to isolate y:

y = -3x + 21 - 17

Simplifying further, we have:

y = -3x + 4

Therefore, the equation of the line with a slope of -3 and passing through the point (7, -17) is y = -3x + 4.

Answer 2

y = -3x + 4

Explanation:

First we will write the equation in point-slope form:

`y-y_1=m(x-x_1)`

Substitute the data.

`y-(-17)=-3(x-7)`

`y+17=-3x+21`

`y=-3x+21-17`

`\boxed{y=-3x+4}`