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Suppose that f(x)=9x^2*ln(x), x>0 (A) List all the critical values of f(x). Note: If there ara nn critinal uali 'es, enter 'NONE',

User Platus
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Answer:

Hi,

Explanation:

There is a minimum for x=0.1353...


y=9x^2*ln(x)\\\\y'=18x*ln(x)+9x^2*1/x=0\\\\18x*ln(x)=-9*x\\\\ln(x)=-(1)/(2) \\\\x=(1)/(e^2) \approx{0.13533..}

User Tim Visher
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