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What is an equation of the line that passes through the points (8,6) and(−3,6)?

User Vihar
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1 Answer

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Explanation:

When two points on a line are given, you can find the equation of the line using the point-slope formula:

y - y1 = m(x - x1)

Where (x1, y1) is one of the points on the line, and "m" is the slope.

In this case, the points are (8, 6) and (-3, 6), which lie on a horizontal line because they both have the same y-coordinate (y = 6).

The slope for a horizontal line is always 0 because it doesn't change in the y-direction. So, we have:

m = 0

Now, let's choose one of the points, say (8, 6), and use the point-slope formula:

y - 6 = 0(x - 8)

Since the slope is 0, the equation simplifies to:

y - 6 = 0

Now, add 6 to both sides of the equation:

y = 6

So, the equation of the line that passes through the points (8, 6) and (-3, 6) is simply:

y = 6

solved by "MG"

User Aeapen
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