Answer:
(11m^4n^4 + 3)(11m^4n^4 - 3)
Explanation:
To write the binomial -9 + 121m^8n^8 as a product, you can factor it using the difference of squares:
-9 + 121m^8n^8 = (11m^4n^4)^2 - 3^2
Now, you have it factored as a difference of squares:
(11m^4n^4 + 3)(11m^4n^4 - 3)