Question

What is the area in square units of a triangle on an XY plane with vertices (2,3) , (9,3) and (5,6)

Answer 1

To find the area of a triangle with vertices (2,3), (9,3), and (5,6) on the XY plane, you can use the formula for the area of a triangle:

Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|

Using the coordinates:

x1 = 2, y1 = 3
x2 = 9, y2 = 3
x3 = 5, y3 = 6

Area = 1/2 * |2(3 - 6) + 9(6 - 3) + 5(3 - 3)|

Area = 1/2 * |-6 + 27 + 0|

Area = 1/2 * 21

Area = 10.5 square units

So, the area of the triangle is 10.5 square units.

Answer 2

To find the area of a triangle on the XY plane with given vertices, you can use the formula for the area of a triangle:

Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|

In this formula, (x1, y1), (x2, y2), and (x3, y3) are the coordinates of the three vertices of the triangle.

In your case, the vertices are (2, 3), (9, 3), and (5, 6). Let's calculate the area:

Area = 1/2 * |2(3 - 6) + 9(6 - 3) + 5(3 - 3)|

Area = 1/2 * |-6 + 27 + 0|

Area = 1/2 * 21

Area = 10.5 square units

So, the area of the triangle is 10.5 square units.